Factorize the expressions and divide them as directed:
\left(m^{2}-14 m-32\right) \div(m+2)
Solution:
A polynomial called a "quadratic" is expressed as "ax2 + bx + c," where "a," "b," and "c" are simple numbers. We can determine the two integers that will add up to equal "b," the coefficient on the x-term, as well as multiply to equal the product term "ac" for factorization.
\begin{aligned} &\text { Solve for } \mathrm{m}^{2}-14 \mathrm{m}-32, \text { we have }\\ &m^{2}-14 m-32=m^{2}+2 m-16 m-32=m(m+2)-16(m+2)=(m-16)(m+2)\\ &\text { Now, } \left.\left(\mathrm{m}^{2}-14 \mathrm{m}-32\right) \div(\mathrm{m}+2)=(\mathrm{m}-16)(\mathrm{m}+2) / \mathrm{m}+2\right)=\mathrm{m}-16 \end{aligned}
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