NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.3 in Chapter 14 - Factorisation

Question 15 Exercise 14.3

Factorize the expressions and divide them as directed:

\left(y^{2}+7 y+10\right) \div(y+5)



A polynomial called a "quadratic" is expressed as "ax2 + bx + c," where "a," "b," and "c" are simple numbers. For a simple case of factoring, we may determine the two values that will add up to equal "b," as well as multiply to equal the product term "ac."

\begin{aligned} &\text { First solve for equation, }\left(y^{2}+7 y+10\right)\\ &\left(y^{2}+7 y+10\right)=y^{2}+2 y+5 y+10=y(y+2)+5(y+2)=(y+2)(y+5)\\ &\text { Now, }\left(y^{2}+7 y+10\right) \div(y+5)=(y+2)(y+5) /(y+5)=y+2 \end{aligned}

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