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NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.3 in Chapter 14 - Factorisation
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Q4) Divide as directed.
(i) 5(2x + 1) (3x + 5) ÷ (2x + 1)
(ii) 26xy(x + 5)(y – 4) ÷ 13x(y – 4)
(iii) 52pqr (p + q) (q + r) (r + p) ÷ 104pq(q + r) (r + p)
(iv) 20\left(y+4\right)\left(y^2+5y+3\right)\div5\left(y+4\right)
(v) x(x + 1) (x + 2) (x + 3) ÷ x(x + 1)
Solution 4:
(i) \frac{5\left(2x+1\right)\left(3x+5\right)}{2x+1}
= 5(3x+5)
(ii) \frac{2\times13\times x\times y\times\left(x+5\right)\times\left(y-4\right)}{13\times x\times\left(y-4\right)}
=2\times y\times\left(x+5\right)
=2y\left(x+5\right)
(iii) \frac{2\times2\times13\times p\times q\times r\times\left(p+q\right)\times\left(q+r\right)\times\left(r+p\right)}{2\times2\times2\times13\times p\times q\times\left(q+p\right)\times\left(r+p\right)}
=\frac{r\left(p+q\right)}{2}
(iv) \frac{20\left(y+4\right)\left(y^2+5y+3\right)}{5\left(y+4\right)}
=4\left(y^2+5y+3\right)
(v)\frac{x\left(x+1\right)\left(x+2\right)\left(x+3\right)}{x\left(x+1\right)}
(x+2)(x+3)
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