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NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.2 in Chapter 14 - Factorisation
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Question 30 Exercise 14.2
Factorise:
p^{2}+6 p-16
Answer:
Solution:
Assuming that a, b, and c are all real numbers, the rule for factoring the trinomial ax2+bx+c is to divide b (the coefficient of x) into two real numbers so that their algebraic sum is b and their product is ac.
We observed that, 16 = -2 x 8 and 8 + (-2) = 6
\begin{array}{l} p^{2}+6 p-16=p^{2}-2 p+8 p-16 \\ =p(p-2)+8(p-2) \\ =(p+8)(p-2) \\ \text { So, } p^{2}+6 p-16=(p+8)(p-2) \end{array}
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