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NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.2 in Chapter 14 - Factorisation
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Q3) Factorise the expressions:
(i) ax^2+bx
(ii) 7p^2+21q^2
(iii) 2x^3+2xy^2+2xz^2
(iv) am^2+bm^2+bn^2+an^2
(v) (lm+1)+m+1
(vi) y(y+z)+9(y+z)
(vii) 5y^2-20y-8z+2yz
(viii) 10ab+4a+5b+2
(ix)6xy-4y+6-9x
Solution3:
(i) x(ax+b)
(ii) 7\left(p^2+3q^2\right)
(iii) 2x\left(x^2+y^2+z^2\right)
(iv) Lets split the expression to am^2+bm^2and\ an^2+bn^2
Therefore, am^2+bm^{2\ }
=\ m^2\left(a+b\right)
and, an^2+bn^2
n^2\left(a+b\right)
On adding these two
m^2\left(a+b\right)\ +n^2\left(a+b\right)
\left(a+b\right)\ \left(m^2+n^2\right)
(v) l(m+1)+m+1
l(m+1)+1(m+1)
(l+1)(m+1)
(vi) (y+z) (y+9)
(vii) Let's split the expression to \left(5y^2-20y\right)\ and\ \left(2yz-8z\right)
= 5y (y-4)
and, 2z(y-4)
on adding the two
5y(y-4) + 2z(y-4)
(5y+2z)(y-4)
(viii) Let's the expression to 10ab +4a and 5b+2
For, 10 ab +4a
= 2a(5b+2)
For, 5b+2
1(5b+2)
now adding the two,
2a(5b+2) +1 (5b+2)
(2a+1) (5b+2)
(ix) Let's split the expression to 6xy-4y and 6-9x
For, 6xy-4y
= 2y (3x-2)
For, 6-9x
-3(-2+3x)
on adding the two expression
2y(3x-2) -3 (3x-2)
= (2y-3) (3x-2)
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