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NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.2 in Chapter 14 - Factorisation

Question 14 Exercise 14.2

Q2) Factorise.

(i) 4p^2-9q^2

(ii) 63a^2-112b^2

(iii) 49x^2-36

(iv) 16x^5-144x^3

(v) \left(l+m\right)^2-\left(l-m\right)^2

(vi) 9x^2y^2-16

(vii)

Answer:

Solution 2:

(i) \left(2p\right)^2-\left(3q\right)^2

\left(2p+3q\right)\left(2p-3q\right)

(ii) 7\left(9a^2-16b^2\right)

7\left[\left(3a\right)^2-\left(4b\right)^2\right]

7\left[\left(3a+4b\right)\left(3a-4b\right)\right]

(iii) \left(7x\right)^2-6^2

\left(7x-6\right)\left(7x+6\right)

(iv) x^3\left(16x^2-144\right)

x^3\left[\left(4x\right)^2-\left(12\right)^2\right]

x^3\left[\left(4x-12\right)\left(4x+12\right)\right]

(v) \left(l^2+m^2+2lm\right)-\left(l^2+m^2-2lm\right)

l^2+m^2+2lm-l^2-m^2+2lm

=4lm

(vi) \left(3xy\right)^2-4^2

(3xy+4) (3xy-4)

(vii) \left(x-y\right)^2-z^2

\left(x-y+z\right)\left(x-y-z\right)

(viii) 25a^{2\ }-\left[\left(2b\right)^2\ -\ 2\times2b\times7c\ +\ \left(7c\right)^2\right]

\left(5a\right)^2-\left[\left(2b-7c\right)^2\right]

\left(5a\right)^2\ -\left(2b-7c\right)^2

(5a+2b-7c) (5a-2b+7c)

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