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Factorise:

(1+m)^{2}-(1-m)^{2}

Answer:

Solution:

\begin{array}{l} =\{(1+\mathrm{m})-(1-\mathrm{m})\}\{(1+\mathrm{m})+(1-\mathrm{m})\} \\ \text { Using Identity: } x^{2}-y^{2}=(x+y)(x-y) \\ =(1+\mathrm{m}-1+\mathrm{m})(1+\mathrm{m}+1-\mathrm{m}) \\ =(2 \mathrm{m})(21) \\ =4 \mathrm{ml} \end{array}

"hello students i am rita your math
leader tutor and the today's question is
factorize 1 plus
m whole raised to power 2 minus
bracket 1 minus m whole raised to power
2. we have to solve this question first
of all we use the identity
first of all x plus y whole square is
equal to x
square plus 2xy plus
y square and the next identity is x
minus y whole
square that is equal to x square minus 2
x y
plus y square and the last identity that
is a
square minus b square
we got a plus b and
a minus b we can use
these three identity in this question
there are two methods to solve first of
all a plus b whole
square we use first one identity and a
minus b whole square we use second
identity and then we solve the question
and the last
second method is we directly use the
third identity that is
x square minus y square is equal to x
plus y
and x minus y so we go through
third identity is x square minus
y square we take it this one is x and
this one is y
and we use this third one identity
then we got a x square minus y square is
x plus
y and the second one is x
minus y so m become plus
because minus minus plus so plus and
minus m cancel out 1 plus 1
2 and plus 1
minus 1 cancel out m plus m
2 n now the answer is 2 two dozer
four amps so this is the answer of this
question
i hope you like this video so please
subscribe d2 for more updates and do
comment your questions
thank you"

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