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Factorise the expression:

4 x^{2}-8 x+4

Answer:

Solution:

There are some identities, and the factorization is much simpler when employing them. Given expressions that need to be factored have the following forms or can be transformed into them: a^{2} - 2ab + b^{2} =(a-b)^{2}

\begin{array}{l} 4 x^{2}-8 x+4 \\ =(2 x)^{2}-2 \times 4 x+2^{2} \\ =(2 x-2)^{2} \\ \text { Using identity: }(x-y)^{2}=x^{2}-2 x y+y^{2} \end{array}

"hello students i am rita your math
leader tutor
and the today's question is factorize
the expression 4x
square minus 8x plus 4
so first of all we write 4x square as
2x into 2x and
4 we can write 2 into 2 and the 8x we
can write as
2 into 2x into 2
now we can write 2x into 2 as 2x whole
raised to power 2 minus 2 into 2x into
2 plus 2 whole raised to power
2 now we use the identity that is
x minus y whole square is equal to a
square minus 2 a b plus
y square now we use this identity and we
got the answer
that is 2x minus 2 whole
square so 2x minus 2
whole square and this is the answer of
this question 2x minus 2 whole square
this is the answer of this question
i hope you like this video so please
subscribe video for more updates and do
comment your questions
thank you"

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