NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.2 in Chapter 14 - Factorisation

Question 28 Exercise 14.2

Factorise the expression:

$4 x^{2}-8 x+4$

Answer:

Solution:

There are some identities, and the factorization is much simpler when employing them. Given expressions that need to be factored have the following forms or can be transformed into them: a² - 2ab + b² =(a-b)²

$\begin{array}{l} 4 x^{2}-8 x+4 \\ =(2 x)^{2}-2 \times 4 x+2^{2} \\ =(2 x-2)^{2} \\ \text { Using identity: }(x-y)^{2}=x^{2}-2 x y+y^{2} \end{array}$

Video transcript

"hello students i am rita your math leader tutor and the today's question is factorize the expression 4x square minus 8x plus 4 so first of all we write 4x square as 2x into 2x and 4 we can write 2 into 2 and the 8x we can write as 2 into 2x into 2 now we can write 2x into 2 as 2x whole raised to power 2 minus 2 into 2x into 2 plus 2 whole raised to power 2 now we use the identity that is x minus y whole square is equal to a square minus 2 a b plus y square now we use this identity and we got the answer that is 2x minus 2 whole square so 2x minus 2 whole square and this is the answer of this question 2x minus 2 whole square this is the answer of this question i hope you like this video so please subscribe video for more updates and do comment your questions thank you"

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