NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.2 in Chapter 14 - Factorisation

Question 1 Exercise 14.2

Factorise the expression:

p^{2}-10 p+25



There are some identities, and the factorization is much simpler when employing them.

The provided expression needs to be factored and has the following form: a2 - 2ab + b2 = (a-b)2.

\begin{array}{l} \mathrm{p}^{2}-10 \mathrm{p}+25 \\ =p^{2}-2 \times 5 \times p+5^{2} \\ =(p-5)^{2} \\ \text { Using identity: }(x-y)^{2}=x^{2}-2 x y+y^{2} \end{array}

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