# NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.2 in Chapter 14 - Factorisation

Question 7 Exercise 14.2

Factorise the expression:

a^2 + 8a + 16

In the factorization using identity, (a+b)2 = a2 + 2ab+ b2, the first and last terms in the identity should both be perfect squares, and the middle term is two times the square root of the first and last term with a positive sign. So here,

\begin{array}{l} a^{2}+8 a+16 \\ =a^{2}+2 \times 4 \times a+4^{2} \\ =(a+4)^{2} \\ \text {Using identity: }(x+y)^{2}=x^{2}+2 x y+y^{2} \end{array}

Video transcript
"hello students i am rita your math leader tutor and the today's question is factorize the expression 4x square minus 8x plus 4 so first of all we write 4x square as 2x into 2x and 4 we can write 2 into 2 and the 8x we can write as 2 into 2x into 2 now we can write 2x into 2 as 2x whole raised to power 2 minus 2 into 2x into 2 plus 2 whole raised to power 2 now we use the identity that is x minus y whole square is equal to a square minus 2 a b plus y square now we use this identity and we got the answer that is 2x minus 2 whole square so 2x minus 2 whole square and this is the answer of this question 2x minus 2 whole square this is the answer of this question i hope you like this video so please subscribe video for more updates and do comment your questions thank you"
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