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Q5) A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle?

Answer:

Let the number of days be x

Total number of animals = 20 + 10 = 30

Here the number of animals and the number of days are in inverse proportion.

\therefore\frac{20}{30}=\frac{x}{6}

x=\frac{6\times20}{30}=\frac{12}{3}=4

Hence the food will last 4 days.

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