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NCERT Solutions Class 8 Mathematics Solutions for Exercise 13.1 in Chapter 13 - Direct and Inverse Proportions

Question 3 Exercise 13.1

Q2) A mixture of paint is prepared by mixing 1 pan of red pigments with 8 parts of the base. In the following table, find the parts of the base that need to be added. Question 3 Image - NCERT Solutions - Mathematics , Class 8 chapter Direct and Inverse Proportions

Answer:

Solution:

The given mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of the base. For more parts of red pigments, the parts of the base will also be more.

Therefore, the parts of red pigments and the parts of the base are in direct proportion. The given information in the form of a table is as follows.

NCERT Solutions - Mathematics , Class 8 chapter Direct and Inverse Proportions Question 3 Solution image

According to direct proportion,

\frac{^x1}{4}=\frac{8}{1}\Rightarrow^x1=\ 4\ \times8=32

\frac{^x2}{7}=\frac{8}{1}\Rightarrow^x2=\ 7\times8=56

\frac{^x3}{12}=\frac{8}{1}\Rightarrow^x2=8\times12\ =\ 96

\frac{^x4}{20}=\frac{8}{1}\Rightarrow^x4=8\times20=160

The table can be drawn as follows.

NCERT Solutions - Mathematics , Class 8 chapter Direct and Inverse Proportions Question 3 Solution image

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