NCERT Solutions Class 8 Mathematics Solutions for Exercise 11.1 in Chapter 11 - Mensuration

Question 8 Exercise 11.1

Q4.A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080m^2 ?


Ans 4. Area of floor=1080\ m^2

To find,

No.of tiles required to cover the floor

=\frac{area\ of\ floor}{area\ of\ 1\ tile}

Area of tile in the shape =base\ \times height

base=24 cm height=10 cm


=240\ cm^2

No.of tiles=\frac{area\ of\ floor}{area\ of\ each\ tile}

=\frac{1080\ m^2}{240\ m^2}

==1080\times100000\div240\ cm^2

=45,000 tiles.

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