\text { Multiply } \frac{b}{13} \text { by the reciprocal of } \frac{-7}{16}
\text { Reciprocal of } \frac{-7}{16}=\frac{16}{-7}=\frac{-16}{7}
According to the question,
\begin{array}{l} \frac{6}{13} \times\left(\text { Reciprocal of } \frac{-7}{16}\right) \\ \Rightarrow \frac{6}{13} \times \frac{-16}{7}=\frac{-96}{91} \end{array}
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