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\text { Multiply } \frac{b}{13} \text { by the reciprocal of } \frac{-7}{16}

Answer:

\text { Reciprocal of } \frac{-7}{16}=\frac{16}{-7}=\frac{-16}{7}

According to the question,

\begin{array}{l} \frac{6}{13} \times\left(\text { Reciprocal of } \frac{-7}{16}\right) \\ \Rightarrow \frac{6}{13} \times \frac{-16}{7}=\frac{-96}{91} \end{array}

"hello guys welcome back to the homework
i'm davin kumar working as a tutor that
we do
so today we are going to solve one very
easy and interesting problem
so let's see how we can do it here so
multiply 6 by 13 by the reciprocal of 16
by -7
so we can do it so multiply 6 by 13
with reciprocal reciprocal of minus 7 by
16 is equal to how much
so that is 16 by minus 7 right
so 16 by minus 7 will be the exact
reciprocal
that is we can say it has inverse also
okay so now 6 by 13
into 16 by minus 7 so that is equals to
16 x is equals to
that is 96 by 91
so here it will be minus so this is our
final answer here so that is minus 96 by
91 also we can say
or else or else 96 by minus 91 also we
can say
but in denominators mostly we'll be not
finding any minus
so it is exactly to the numerator so i
hope you understood what it is thinking
of the like what i've done here
if you have any doubts please comment
below don't forget to subscribe to this
channel
thank you so much for watching this and
stay tuned thank you
"

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