Ncert solutions

Ncert solutions

Grade 7

Comparing Quantities | Exercise 8.1

Question 1

Q1) Find the ratio of:

(a) Rs. 5 to 50 paise

(b) 15 kg to 210 g

(c) 9 m to 27 cm

(d) 30 days to 36 hours

Solution:

To find ratios, both quantities should be in the same unit.

(a) Rs. 5 to 50 paise

5 x 100 paise to 50 paise

\left[\because Rs.1=100paise\right]

500 paise to 50 paise

Thus, the ratio is = \frac{500}{50}=\frac{10}{1}=10:1

(b) 15 kg to 210 g

15 x 1000 g to 210 g \left[\because1\ kg=1000g\right]

15000 g to 210 g

Thus, the ratio is = \frac{15000}{210}=\frac{500}{7}=500:7

(c) 9 m to 27 cm

9 x 100 cm to 27 cm \left[\because1\ m\ =100\ cm\right]

900 cm to 27 cm

Thus, the ratio is = \frac{900}{27}=\frac{100}{3}=100:3

(d) 30 days to 36 hours

30 x 24 hours to 36 hours \left[\because1\ day\ =\ 24\ hours\right]

720 hours to 36 hours

Thus, the ratio is = \frac{720}{36}=\frac{20}{1}=20:1

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Question 1

Q1) Find the ratio of:

(a) Rs. 5 to 50 paise

(b) 15 kg to 210 g

(c) 9 m to 27 cm

(d) 30 days to 36 hours

Solution:

To find ratios, both quantities should be in the same unit.

(a) Rs. 5 to 50 paise

5 x 100 paise to 50 paise

\left[\because Rs.1=100paise\right]

500 paise to 50 paise

Thus, the ratio is = \frac{500}{50}=\frac{10}{1}=10:1

(b) 15 kg to 210 g

15 x 1000 g to 210 g \left[\because1\ kg=1000g\right]

15000 g to 210 g

Thus, the ratio is = \frac{15000}{210}=\frac{500}{7}=500:7

(c) 9 m to 27 cm

9 x 100 cm to 27 cm \left[\because1\ m\ =100\ cm\right]

900 cm to 27 cm

Thus, the ratio is = \frac{900}{27}=\frac{100}{3}=100:3

(d) 30 days to 36 hours

30 x 24 hours to 36 hours \left[\because1\ day\ =\ 24\ hours\right]

720 hours to 36 hours

Thus, the ratio is = \frac{720}{36}=\frac{20}{1}=20:1

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subject-cta
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