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NCERT Solutions Class 7 Mathematics Solutions for Exercise 6.5 in Chapter 6 - The Triangle and its properties
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Q3) A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.
Answer:
Solution 3:
Let AC be the ladder, and A be the window
h^2=\ b^2+p^2
\left(15\right)^2\ =\ \left(a\right)^2\ +\ \left(12\right)^2
225\ -\ 144\ =\ a^2
81\ =\ a^2
\sqrt{81}\ =\ a
a = 9
Video transcript
Hello guys, welcome to lido homework
today we're looking at question numbers.
three which is a 15-meter long ladder
reached the window 12 meters high
from the ground and placing it against
the wall at a distance a
find the distance at the foot of the
the ladder from the wall so here's what we're
going to use
is your Pythagoras theorem so Pythagoras
Theorem is
h square which is hypotenuse square okay
so hypotenuse square
is equal to sorry
is equal to a square which is one side
plus b square which is another
so let's calculate it hypertension this
was given to us as 15 square so 15 square
is equal to square so one side is 12
row 12 meters or 12 squared
Plus, the square 15 square is 225
225 is equal to 144
Plus the square next step that we'll be doing is
We'll subtract them so a square
is equal to 225 minus 144 taking 140 for
this side
okay so 225 minus 144 will
will give you the answer as 81 so a square
will be equal to 81
now you just need to find the square
the root of 81 so the square root of 81
is obviously 9 therefore a will be equal
to 9 meter
thank you so much guys, please like the
video and subscribe to the channel
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