Ncert solutions

Ncert solutions

Grade 7

The Triangle and its properties | Exercise 6.5

Question 1

Q1) PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

Solution1 :

Let the RQ be x cm,

In right angle triangle PQR,

h^2\ =\ b^2+p^2

QR^2\ =\ PQ^2\ +PR^2\

x^2=\ \left(10\right)^2+\left(24\right)^2

x^2\ =\ 100\ +576

x\ =\ \sqrt{100+576}

x\ =\ \sqrt{676}

x = 26 cm

Thus, the length of QR is 26cm.

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subject-cta

Question 1

Q1) PQR is a triangle, right-angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

Solution1 :

Let the RQ be x cm,

In right angle triangle PQR,

h^2\ =\ b^2+p^2

QR^2\ =\ PQ^2\ +PR^2\

x^2=\ \left(10\right)^2+\left(24\right)^2

x^2\ =\ 100\ +576

x\ =\ \sqrt{100+576}

x\ =\ \sqrt{676}

x = 26 cm

Thus, the length of QR is 26cm.

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your mathematics exam ?

Learn from an expert tutor.

Book a free class now
subject-cta
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