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CHAPTERS
1. Chapter 1- Rational and Irrational Numbers
2. Chapter 2- Compound Interest [Without Using Formula
3. Chapter 3- Compound Interest [Using Formula
6. Chapter 6- Simultaneous Equations
7. Chapter 7- Indices [exponents]
9. Chapter 9- Triangles [Congruency in Triangles]
10. Chapter 10- Isosceles Triangle
12. Chapter 12- Mid-Point and Its Converse
13. Chapter 13- Pythagoras Theorem
14. Chapter 14- Rectilinear Figures
15. Chapter 15- Construction of Polygons
19. Chapter 19- Mean and Median
20. Chapter 20- Area and Perimeter of Plane Figures
22. Chapter 22- Trigonometrical Ratios
23. Chapter 23- Trigonometrical Ratios of Standard Angles
24. Chapter 24- Solution Of Right Triangles
25. Chapter 25- Complementary angles
26. Chapter 26- Co-ordinate Geometry
A man borrows Rs.10,000 at 10% compound interest compounded yearly.
At the end of each year, he pays back 30% of the sum borrowed. How much money is left unpaid just after the second year?
Solution
Transcript
For 1st year
P= Rs10,000; R=10% and T= 1year
Interest= Rs \frac{10,000 \times 10 \times 1}{100}=\mathrm{Rs} 1,000
Amount at the end of 1st year=Rs10,000+Rs1,000=Rs11,000
Money paid at the end of 1st year=30% of Rs10,000=Rs3,000
Principal for 2nd year=Rs11,000- Rs3,000=Rs8,000
For 2nd year
P=Rs8,000; R=10% and T= 1year
Interest= Rs \frac{8,000 \times 10 \times 1}{100}=\mathrm{Rs} 800
Amount at the end of 2nd year=Rs8,000+Rs800= Rs8,800
Money paid at the end of 2nd year=30% of Rs10,000= Rs3,000
Principal for 3rd year=Rs8,800- Rs3,000=Rs5,800 .
"hi i am shivani your math tutor from lido now we are having a question where we need to find the compound interest and tell that how much money is left with him after the second year so let's first examine the question it is a man borrows rupees 10 000 at 10 interest which is compounded yearly and at the end of each year he pays back 30 percent of what the sum he borrowed which is rupees 10 000 so how much money is left unpaid just after the second year let's proceed to the solution first we shall find the interest for the first year it will be principal into rate into time by 100 our principal is rupees 10 000 rate is 10 percent and time is one year by 100 we get rupees 1000 so how much he paid at the end of first year it will be thirty percent of ten thousand means he paid rupees three thousand back now what's left the principle it will be 11 000 minus 3000 equals to 8 000 this is the amount left with him to be paid now the interest for the second year on this amount will be eight thousand rate is same ten percent time is one year by hundred from here we get rupees 800 now the amount becomes rupees 8000 plus rupees 800 equals to rupees 88 hundred and what he did at the second year he again paid a rupees 3000 back so the amount left to be paid is this rupees 8 800. minus this rupees 3000 as he paid this back so the amount left is rupees 58 100. this is the required solution for more such videos subscribe to lido and if you have any queries drop in the comment section thank you"
Chapter 1- Rational and Irrational Numbers
Chapter 2- Compound Interest [Without Using Formula
Chapter 3- Compound Interest [Using Formula
Chapter 6- Simultaneous Equations
Chapter 7- Indices [exponents]
Chapter 9- Triangles [Congruency in Triangles]
Chapter 10- Isosceles Triangle
Chapter 12- Mid-Point and Its Converse
Chapter 13- Pythagoras Theorem
Chapter 14- Rectilinear Figures
Chapter 15- Construction of Polygons
Chapter 20- Area and Perimeter of Plane Figures
Chapter 22- Trigonometrical Ratios
Chapter 23- Trigonometrical Ratios of Standard Angles
Chapter 24- Solution Of Right Triangles
Chapter 25- Complementary angles
Chapter 26- Co-ordinate Geometry
A man borrows Rs.10,000 at 10% compound interest compounded yearly.
At the end of each year, he pays back 30% of the sum borrowed. How much money is left unpaid just after the second year?
Solution
Transcript
For 1st year
P= Rs10,000; R=10% and T= 1year
Interest= Rs \frac{10,000 \times 10 \times 1}{100}=\mathrm{Rs} 1,000
Amount at the end of 1st year=Rs10,000+Rs1,000=Rs11,000
Money paid at the end of 1st year=30% of Rs10,000=Rs3,000
Principal for 2nd year=Rs11,000- Rs3,000=Rs8,000
For 2nd year
P=Rs8,000; R=10% and T= 1year
Interest= Rs \frac{8,000 \times 10 \times 1}{100}=\mathrm{Rs} 800
Amount at the end of 2nd year=Rs8,000+Rs800= Rs8,800
Money paid at the end of 2nd year=30% of Rs10,000= Rs3,000
Principal for 3rd year=Rs8,800- Rs3,000=Rs5,800 .
"hi i am shivani your math tutor from lido now we are having a question where we need to find the compound interest and tell that how much money is left with him after the second year so let's first examine the question it is a man borrows rupees 10 000 at 10 interest which is compounded yearly and at the end of each year he pays back 30 percent of what the sum he borrowed which is rupees 10 000 so how much money is left unpaid just after the second year let's proceed to the solution first we shall find the interest for the first year it will be principal into rate into time by 100 our principal is rupees 10 000 rate is 10 percent and time is one year by 100 we get rupees 1000 so how much he paid at the end of first year it will be thirty percent of ten thousand means he paid rupees three thousand back now what's left the principle it will be 11 000 minus 3000 equals to 8 000 this is the amount left with him to be paid now the interest for the second year on this amount will be eight thousand rate is same ten percent time is one year by hundred from here we get rupees 800 now the amount becomes rupees 8000 plus rupees 800 equals to rupees 88 hundred and what he did at the second year he again paid a rupees 3000 back so the amount left to be paid is this rupees 8 800. minus this rupees 3000 as he paid this back so the amount left is rupees 58 100. this is the required solution for more such videos subscribe to lido and if you have any queries drop in the comment section thank you"
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