Ncert solutions

Grade 7

# Question 1

Q1) Find

i) 0.4\div2\ \

ii) 0.35\div5\

iii) 2.48\div4\

iv) 65.4\div6\

v) 651.2\div4\

vi) \ 14.49\div7\

vii) 3.96\div4\ \

viii) 0.80\div5

Solution 1

i) 0.4\div2\ \

= \frac{4}{10}\times\ \frac{1}{2}=\ \frac{2}{10}\ =\ 0.2

ii) 0.35\div5\

= \frac{35}{100}\ \frac{1}{5}=\frac{7}{100}=0.07

iii) 2.48\div4\

= \frac{248}{100}\ \times\frac{1}{4}\ =\ \frac{63}{100}=\ 0.62

iv) 65.4\div6\

= \frac{654}{10}\times\frac{1}{6}=\ \frac{109}{10}\ =10.9

v) 651.2\div4\

= \frac{6512}{10}\ \times\frac{1}{4}=\ \frac{1628}{10}=\ 162.8

vi) \ 14.49\div7\

= \frac{1449}{100\ }\times\frac{1}{7}=\ \frac{207}{100}\ =\ 2.07

vii) 3.96\div4\ \

=\frac{396}{100}\ \times\frac{1}{4}=\ \frac{99}{100}=0.99

viii) 0.80\div5

= \frac{80}{100}\ \times\frac{1}{5}=\frac{16}{100}=\ 0.16

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