Perimeter and Area | Exercise 11.3

Question

Q13) A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? $\left(\pi=3.14\right)$

Accepted Answer

Solution 13:

Diameter of the flower bed= 66m

Radius= $\frac{66}{2}=33m$

Width of the path= 4m

Radius of the flower bed included path

=33m+4m=37m

Let $r_2=37m$

Area of the circular path= $\pi\left(r\binom{2}{2}-r\binom{2}{1}\right)$

$=3.14\left(37^2-33^2\right)$

$=3.14\times\left(37+33\right)\left(37-33\right)\left[Y\ a^2-b^2=\left(a+b\right)\left(a-b\right)\right]$

$=3.14\times70\times4=879.20m^2$

Hence, the required area= $879.20m^2$

Perimeter and Area | Exercise 11.3

Chapters in NCERT Solutions - Mathematics, Class 7

Exercises in Perimeter and Area

Question 17