NCERT Solutions Class 7 Mathematics Solutions for Exercise 11.3 in Chapter 11 - Perimeter and Area

Question 17 Exercise 11.3

Q13) A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? $\left(\pi=3.14\right)$

Answer:

Solution 13:

Diameter of the flower bed= 66m

Radius= $\frac{66}{2}=33m$

Width of the path= 4m

Radius of the flower bed included path

=33m+4m=37m

Let $r_2=37m$

Area of the circular path= $\pi\left(r\binom{2}{2}-r\binom{2}{1}\right)$

$=3.14\left(37^2-33^2\right)$

$=3.14\times\left(37+33\right)\left(37-33\right)\left[Y\ a^2-b^2=\left(a+b\right)\left(a-b\right)\right]$

$=3.14\times70\times4=879.20m^2$

Hence, the required area= $879.20m^2$

Related Questions

Find the Circumference of the Circle with the following Radius: (Take π = 22/7) 21 cm

Q1) Find the circumference of the circles with the following radius: Take [[> widget id="1"<]](a) 14...

Find the area of the following circles, given that:Radius = 14 mm (Take π = 22/7)

Q2) Find the area of the following circles, given that:(a) radius = 14 mm (Take(b) diameter = 49 m(c...

If the circumference of a circular sheet is 154 m, find its radius. Also find the area of the sheet....

Q4) A gardener wants to fence a circular garden of diameter 21m. Find the length of the rope he need...

Exercises

Exercise 11.1

Exercise 11.2

Exercise 11.3

Exercise 11.4

Chapters

Integers

Fractions and Decimals

Data Handling

Simple Equations

Lines and Angles

The Triangle and its properties

Congruence of Triangles

Comparing Quantities

Rational Numbers

Practical Geometry

Perimeter and Area

Algebraic Expressions

Exponents and Powers

Symmetry

Visualising Solid Shapes