Ncert solutions

Ncert solutions

Grade 7

Perimeter and Area | Exercise 11.3

Question 9

Q10) From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take \pi=\frac{22}{7}

Solution 10:

Radius of the circular sheet= 14cm

Area= \pi r^2=\frac{22}{7}\times14\times14cm^2

=616cm^2

Area of 2 small circles= 2\pi r^2

=2\times\frac{22}{7}\times3.5\times3.5cm^2

=77.0cm^2

Area of the rectangle= l\times b

=3\times1cm^2=3cm^2

Area of the remaining sheet after removing the 2 circles and 1 rectangle

=616cm^2-\ \left(77+3\right)cm^2

=616cm^2-\ 80cm^2=536cm^2

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subject-cta

Question 9

Q10) From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take \pi=\frac{22}{7}

Solution 10:

Radius of the circular sheet= 14cm

Area= \pi r^2=\frac{22}{7}\times14\times14cm^2

=616cm^2

Area of 2 small circles= 2\pi r^2

=2\times\frac{22}{7}\times3.5\times3.5cm^2

=77.0cm^2

Area of the rectangle= l\times b

=3\times1cm^2=3cm^2

Area of the remaining sheet after removing the 2 circles and 1 rectangle

=616cm^2-\ \left(77+3\right)cm^2

=616cm^2-\ 80cm^2=536cm^2

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your mathematics exam ?

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subject-cta
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