Ncert solutions

Ncert solutions

Grade 7

Integers | Exercise 1.4

Question 1

Q1) Evaluate each of the following:

(a) (–30) ÷ 10

(b) 50 ÷ (–5)

(c) (–36) ÷ (–9)

(d) (– 49) ÷ (49)

(e) 13 ÷ [(–2) + 1]

(f) 0 ÷ (–12)

(g) (–31) ÷ [(–30) + (–1)]

(h) [(–36) ÷ 12] ÷ 3

(i) [(– 6) + 5)] ÷ [(–2) + 1]

Solution 1:

(a) -30\ \times\frac{1}{10}

= -3

(b) 50\times\frac{-1}{5}

= -10

(c) -36\ \times\frac{-1}{9}

= 4

(d) \left(-49\right)\times\frac{1}{49}

= -1

(e) 13\times\left[\left(-2\right)\ +\ 1\right]

13\times\frac{-1}{1}

= -13

(f) 0\times\frac{-1}{12}

= 0

(g) \left(-31\right)\div\left[\left(-30\right)-1\right]

\left(-31\right)\div\left(-31\right)

-31\ \times\frac{-1}{31}

= 1

(h)\left[\left(-36\right)\div12\right]\div3

\left[\left(-36\right)\times\frac{1}{12}\right]\times\frac{1}{3}

\frac{-36}{12}\times\frac{1}{3}

-3\times\frac{1}{3}

= 1

(i) \left[-6+5\right]\div\left[-2+1\right]

-1\times\frac{-1}{1}

= 1

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subject-cta

Question 1

Q1) Evaluate each of the following:

(a) (–30) ÷ 10

(b) 50 ÷ (–5)

(c) (–36) ÷ (–9)

(d) (– 49) ÷ (49)

(e) 13 ÷ [(–2) + 1]

(f) 0 ÷ (–12)

(g) (–31) ÷ [(–30) + (–1)]

(h) [(–36) ÷ 12] ÷ 3

(i) [(– 6) + 5)] ÷ [(–2) + 1]

Solution 1:

(a) -30\ \times\frac{1}{10}

= -3

(b) 50\times\frac{-1}{5}

= -10

(c) -36\ \times\frac{-1}{9}

= 4

(d) \left(-49\right)\times\frac{1}{49}

= -1

(e) 13\times\left[\left(-2\right)\ +\ 1\right]

13\times\frac{-1}{1}

= -13

(f) 0\times\frac{-1}{12}

= 0

(g) \left(-31\right)\div\left[\left(-30\right)-1\right]

\left(-31\right)\div\left(-31\right)

-31\ \times\frac{-1}{31}

= 1

(h)\left[\left(-36\right)\div12\right]\div3

\left[\left(-36\right)\times\frac{1}{12}\right]\times\frac{1}{3}

\frac{-36}{12}\times\frac{1}{3}

-3\times\frac{1}{3}

= 1

(i) \left[-6+5\right]\div\left[-2+1\right]

-1\times\frac{-1}{1}

= 1

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