 # NCERT Solutions Class 6 Mathematics Solutions for Exercise 1.2 in Chapter 1 - Knowing Our Numbers

A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.

Number of tickets sold on 1st day = 1094

Number of tickets sold on 2nd day = 1812

Number of tickets sold on 3rd day = 2050

Number of tickets sold on 4th day = 2751

Hence, number of tickets sold on all the four days = 1094 + 1812 + 2050 + 2751 = 7707 tickets

Video transcript
"hello students welcome to lead q a video session i'm saf your maths tutor and question for today is write down the coordinates of each of the following points a b c d and e so you have to see the figure and see the graph how points a b c d and e are located in it so here first of all we will drop some perpendicular from each of these respective coordinates to x and y axis so here from coordinates dropping perpendicular two first is x axis on x axis you can see we have dropped perpendicular such as af c h j e d i and bg and for y-axis you can see we have draw perpendicular am cp eo nd and b cube now we can plot each of the point given for point a you have distance from the x axis distance from the x axis is am for point a which will be equal to you can see its measure is minus 6 units and distance from y axis that is af which is equal to 5 units so here combinedly for both the distances we can plot the point of coordinate point a has coordinates minus six and five similarly we'll proceed further for point b you can see for point b distance from x axis is qb which is 5 units and for distance from y axis that is bg which is equal to you can see 4 unit is there so point b has coordinates point b has coordinates you can say 5 4 now for point c for point c distance from y axis which is ch and ch has the measure of 2 units and distance from x axis for point c that is cp which has the measure of minus 3 units as in this case we can write the coordinates as point c has coordinates minus 3 2. now point d for point d you can see for point d we have distance from y axis is nd which is two units this and is the for the distance for the x-axis so let me write it here for x-axis and d um yes for x-axis andy which is two units and you have distance from y-axis which is d i which is equal to minus 2 units as in this case point d has coordinates from the figure we can write point d has coordinates 2 minus 2 let us look at point e for point [Music] e you can see distance from x axis is -1 unit that is e 0 minus 1 units and distance from y axis that is ej which is equal to minus 4 units as in this case point e has coordinate minus one minus four now there is one more which is remaining that is we have a b c d e okay the five points which are given is completed over here let us plot them respectively on each of the following graphs so each of the point point a minus 6 5 point b point b is 5 4 point c point c over here is minus 3 2 point t point d over here is 2 minus 2 and point e point e over here is minus 1 minus 4 in this way we have to identify each of the perpendiculars to each of the axis and measure the distance with respect to x and y axis and plot x and y coordinates so if you have any doubts regarding this you can drop it down it in your comment section and please subscribe to our channel for more such interesting question thank you for watching "
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