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NCERT Solutions Class 6 Mathematics Solutions for Exercise 1.2 in Chapter 1 - Knowing Our Numbers
Question 1 Exercise 1.2
A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
Answer:
Number of tickets sold on 1st day = 1094
Number of tickets sold on 2nd day = 1812
Number of tickets sold on 3rd day = 2050
Number of tickets sold on 4th day = 2751
Hence, number of tickets sold on all the four days = 1094 + 1812 + 2050 + 2751 = 7707 tickets
Video transcript
"hello students welcome to lead q a video
session
i'm saf your maths tutor and question
for today is
write down the coordinates of each of
the following points a b c
d and e so you have to see the figure
and see the graph
how points a b c d and e are located in
it
so here first of all we will drop some
perpendicular from each of these
respective coordinates to x and y
axis so here
from coordinates
dropping perpendicular
two first is x axis
on x axis you can see we have dropped
perpendicular such as
af c
h
j e
d i
and bg
and for y-axis
you can see we have draw perpendicular
am
cp
eo
nd
and b cube
now we can plot each of the point given
for point a
you have distance from the x axis
distance from the x axis is am for point
a
which will be equal to you can see its
measure is minus 6 units
and distance from y axis
that is af which is equal to 5 units
so here combinedly for both the
distances we can plot the point of
coordinate
point a has coordinates
minus six and five similarly we'll
proceed further
for point b
you can see for point b distance from x
axis
is
qb
which is 5 units
and for
distance from y axis
that is bg
which is equal to you can see 4 unit is
there
so point b
has coordinates
point b has coordinates you can say 5
4 now for point c
for point c
distance from y axis
which is ch and ch has the
measure of 2 units
and distance from
x axis for point c
that is cp which has the measure of
minus 3 units
as in this case we can write the
coordinates as
point c has
coordinates
minus 3 2.
now point d for point d
you can see for point d we have
distance from y axis
is nd which is two units
this and is the for the distance for the
x-axis so let me
write it here for x-axis and d
um yes for x-axis
andy which is two units
and you have distance from y-axis
which is d i
which is equal to minus 2 units
as in this case point d
has coordinates
from the figure we can write point d has
coordinates
2 minus 2
let us look at point e for point
[Music]
e
you can see distance from x axis
is -1 unit that is e
0
minus 1 units and distance from y axis
that is ej
which is equal to minus 4 units
as in this case point e has coordinate
minus one minus four
now there is one more which is remaining
that is
we have a b c d e okay the five points
which are given is completed over here
let us plot
them respectively on each of the
following
graphs so each of the point point a
minus 6 5
point b point b is
5 4
point c point c over here
is minus 3
2 point t point d over here
is 2 minus 2
and point e point e over here is
minus 1 minus 4 in this way we have to
identify
each of the perpendiculars to each of
the axis
and measure the distance with respect to
x and y axis and plot
x and y coordinates so if you have any
doubts regarding this
you can drop it down it in your comment
section
and please subscribe to our channel for
more such interesting question
thank you for watching
"
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