Ncert solutions

Ncert solutions

Grade 6

Playing With Numbers | Exercise 3.5

Question 10

Q11) 18 is divisible by both 2 and 3. It is also divisible by 2 × 3 = 6. Similarly, a number

is divisible by both 4 and 6. Can we say that the number must also be divisible by

4 × 6 = 24? If not, give an example to justify your answer.

SOLUTION:

We know that if a number is divisible by two co-prime numbers, then it is divisible by their product also. there 2 and 3 are co-prime numbers.

but 4 and 6 are not co-prime numbers, so the number divisible by 4 and 6 will not be divisible by 4\times6=24

take the number 60. it is divisble by both 4 and 6, but it is not divisible by its product i.e 6\times4=24

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subject-cta

Question 10

Q11) 18 is divisible by both 2 and 3. It is also divisible by 2 × 3 = 6. Similarly, a number

is divisible by both 4 and 6. Can we say that the number must also be divisible by

4 × 6 = 24? If not, give an example to justify your answer.

SOLUTION:

We know that if a number is divisible by two co-prime numbers, then it is divisible by their product also. there 2 and 3 are co-prime numbers.

but 4 and 6 are not co-prime numbers, so the number divisible by 4 and 6 will not be divisible by 4\times6=24

take the number 60. it is divisble by both 4 and 6, but it is not divisible by its product i.e 6\times4=24

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subject-cta
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