Ncert solutions

Ncert solutions

Grade 6

Whole Numbers | Exercise 2.2

Question 1

Q1) Find the sum by suitable rearrangement:

(a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 647

Solution 1:

(a) 837+208+363

=(837+363)+208

=1200+208

=1408

(b) 1962+453+1538+647

= (1962+1538) + (453+647)

= 4600

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subject-cta

Question 1

Q1) Find the sum by suitable rearrangement:

(a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 647

Solution 1:

(a) 837+208+363

=(837+363)+208

=1200+208

=1408

(b) 1962+453+1538+647

= (1962+1538) + (453+647)

= 4600

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your mathematics exam ?

Learn from an expert tutor.

Book a free class now
subject-cta
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