Ncert solutions

Ncert solutions

Ncert solutions

Grade 6

CHAPTERS

16) Present age of father is 42 years and that of his son is 14

years. Find the ratio of

(a) Present age of father to the present age of son.

(b) Age of the father to the age of son, when son was 12

years old.

(c) Age of father after 10 years to the age of son after 10 years.

(d) Age of father to the age of son when father was 30 years old.

Solution 16:

(a) Ratio of father’s present age to that of son= \frac{42}{14}=\frac{3}{1}=3:1

(b) When son was 12 years, i.e., 2 years ago, then father was (42 – 2) = 40 years

Therefore, the ratio of their ages = \frac{42}{14}=\frac{3}{1}=3:1

(c) Age of father after 10 years = 42 + 10 = 52 years

Age of son after 10 years = 14 + 10 = 24 years

Therefore, ratio of their ages = \frac{42}{14}=\frac{3}{1}=3:1

(d) When father was 30 years old, i.e., 12 years ago, then son was (14 – 12) = 2 years old

Therefore, the ratio of their ages = \frac{30}{2}=\frac{15}{1}=15:1

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Book a free class now16) Present age of father is 42 years and that of his son is 14

years. Find the ratio of

(a) Present age of father to the present age of son.

(b) Age of the father to the age of son, when son was 12

years old.

(c) Age of father after 10 years to the age of son after 10 years.

(d) Age of father to the age of son when father was 30 years old.

Solution 16:

(a) Ratio of father’s present age to that of son= \frac{42}{14}=\frac{3}{1}=3:1

(b) When son was 12 years, i.e., 2 years ago, then father was (42 – 2) = 40 years

Therefore, the ratio of their ages = \frac{42}{14}=\frac{3}{1}=3:1

(c) Age of father after 10 years = 42 + 10 = 52 years

Age of son after 10 years = 14 + 10 = 24 years

Therefore, ratio of their ages = \frac{42}{14}=\frac{3}{1}=3:1

(d) When father was 30 years old, i.e., 12 years ago, then son was (14 – 12) = 2 years old

Therefore, the ratio of their ages = \frac{30}{2}=\frac{15}{1}=15:1

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