  Ncert solutions

# Question 1

(a) Take Sarita’s present age to be y years.

(i) What will be her age 5 years from now?

(ii) What was her age 3 years back?

(iii) Sarita’s grandfather is 6 times her age. What is the age of her grandfather?

(iv) The grandmother is 2 years younger than grandfather. What is the grandmother’s age?

(v) Sarita’s father’s age is 5 years more than 3 times Sarita’s age. What is her father’s age?

(b) The length of a rectangular hall is 4 meters less than 3 times the breadth of the hall. What is the length, if the breadth is b meters?

(c) A rectangular box has height h cm. Its length is 5 times the height and breadth is 10 cm less than the length. Express the length and the breadth of the box in terms of the height.

(d) Meena, Beena, and Leena are climbing the steps to the hilltop. Meena is at step s, Beena is 8 steps ahead and Leena 7 steps behind. Where are Beena and Meena? The total number of steps to the hilltop is 10 less than 4 times what Meena has reached. Express the total number of steps using s.

(e) A bus travels at v km per hour. It is going from Daspur to Beespur. After the bus has traveled for 5 hours. Beespur is still 20 km away. What id the distance from Daspur to Beespur? Express it using v.

Solution:

(a)

(i) y+5

(ii) y–3

(iii) 6y

(iv) 6y–2

(v) 3y+5

(b) Length = 3b and Breadth = (3b–4) meters

(c) Height of the box = h cm

Length of the box = 5 times the height = 5h cm

Breadth of the box = 10 cm less than length = (5h–10) cm

(d) Meena’s position = s

Beena’s position = 8 steps ahead = s+8

Leena’s position = 7 steps behind = s–7

Total number of steps = 4s–10

(e) Speed of the bus = v km/h

Distance travelled in 5 hours = 5v km

Remaining distance = 20 km

Therefore, total distance = (5v+20) km

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