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Solve for x:

\log _{3}(x+1)-1=3+\log _{3}(x-1)

Answer:

Given

x = 82/80

= 41/40

= **1 1/40**

"hey kids welcome to lido q a video
i am vineeth your little tutor glad to
bring you this question on your screen
solve for x log x plus 1 base 3
minus 1 is equal to 3 plus log
x minus 1 base 3 now
we can write this as
log x plus 1 base 3
minus
log x minus 1 base 3 is equal to 3 plus
1 so this implies
log x plus 1 by x minus 1 base 3
because log a minus log b is log a by b
is equal to 4
right so we can say 4
4 log 3 base 3 because
log 3 base 3 is 1
therefore log x plus 1 by
x minus 1. base 3
is equal to log 3 to the power 4
base 3 so we can say x plus 1 by
x minus 1 is equal to 81
so this implies x plus 1 is equal to
81x minus e2
so this implies atx is equal to
82 therefore x is equal to
82 by 80 or
41 by 40.
isn't that easy guys if you still have
it out please leave a comment below
do like the video and subscribe to our
channel i'll see you in our next video
until then bye kids keep practicing"

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