2 men and 5 women can do a piece of work in 4 days, while one man and one woman can finish
it in 12 days. How long would it take for 1 man to do the work?
Let’s assume that 1 man takes x days to do work and y days for women.
So, the amount of work done by 1 man in 1 day = 1/x
And the amount of work done by 1 woman in 1 day = 1/y
Now,
The amount of work done by 2 men in 1 day will be = 2/x
And the amount of work done by 5 women in 1 day = 5/y
Then according to the given conditions in the problem, we have
2/x + 5/y = ¼ … (i)
1/x + 1/y = 1/12 … (ii)
Multiplying equation (ii) by 5, we get
5/x + 5/y = 5/12
2/x + 5/y = ¼
(-)—(-)---(-)
3/x = 5/12 – ¼
3/x = (5 - 3)/12
3/x = 2/12 = 1/6
x = 18
Therefore, 1 man can do the work in 18 days.
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