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ML Aggarwal Solutions Class 9 Mathematics Solutions for Trigonometric Ratios Exercise 17 in Chapter 17 - Trigonometric Ratios

Question 8 Trigonometric Ratios Exercise 17

If cosec = √5 and is less than 90, find the value of cot - Cos

Answer:

Given cosec θ = √5/1 = OP/PM

OP = √5 and PM = 1

M L Aggarwal - Understanding ICSE Mathematics - Class 9 chapter Trigonometric Ratios Question 8 Solution image

Now \mathrm{OP}^{2}=\mathrm{OM}^{2}+\mathrm{PM}^{2} using Pythagoras theorem

\begin{array}{l} (\sqrt{5})^{2}=O M^{2}+1^{2} \\ 5=O M^{2}+1 \\ O M^{2}=5-1 \\ O M^{2}=4 \\ O M=2 \end{array}

Now cot θ = OM/PM

= 2/1

= 2

Cos θ = OM/OP

= 2/√5

Now cot θ - Cos θ = 2 – (2/√5)

= 2 (√5 – 1)/ 2/√5

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