# ML Aggarwal Solutions Class 9 Mathematics Solutions for Mensuration Exercise 16.4 in Chapter 16 - Mensuration

Question 5 Mensuration Exercise 16.4

A closed rectangular box has inner dimensions 90 cm by 80 cm by 70 cm. Calculate its capacity and the

area of tin-foil needed to line its inner surface.

It is given that

Inner length of rectangular box = 90 cm

Inner breadth of rectangular box = 80 cm

Inner height of rectangular box = 70 cm

We know that

Capacity of rectangular box = volume of rectangular box = l × b × h

Substituting the values

= 90 × 80 × 70

=504000 \mathrm{cm}^{3}

Here

Required area of tin foil = 2 (lb + bh + lh)

Substituting the values

= 2 (90 × 80 + 80 × 70 + 90 × 70)

By further calculation

= 2 (7200 + 5600 + 6300)

So we get

= 2 × 19100

=38200 \mathrm{cm}^{2}

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