A closed rectangular box has inner dimensions 90 cm by 80 cm by 70 cm. Calculate its capacity and the
area of tin-foil needed to line its inner surface.
It is given that
Inner length of rectangular box = 90 cm
Inner breadth of rectangular box = 80 cm
Inner height of rectangular box = 70 cm
We know that
Capacity of rectangular box = volume of rectangular box = l × b × h
Substituting the values
= 90 × 80 × 70
=504000 \mathrm{cm}^{3}
Here
Required area of tin foil = 2 (lb + bh + lh)
Substituting the values
= 2 (90 × 80 + 80 × 70 + 90 × 70)
By further calculation
= 2 (7200 + 5600 + 6300)
So we get
= 2 × 19100
=38200 \mathrm{cm}^{2}
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