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ML Aggarwal Solutions Class 9 Mathematics Solutions for Circle Exercise 15.2 in Chapter 15 - Circle
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Question 2 Circle Exercise 15.2
A and B are points on a circle with center O. C is a point on the circle such that OC
bisects ∠AOB, prove that OC bisects the arc AB.
Answer:
Given: in a given circle with center O, A
And B is Two points on the circle. C i
another point on the circle such that
∠AOC = ∠BOC
To prove : arc AC = arc BC
Proof: OC is the bisector of ∠AOB
Or ∠AOC = ∠BOC
But these are the angle subtended by the
arc AC and BC
arc AC = arc BC.
Video transcript
"hello and welcome my dear students
i am rishabh quran the man student on
lido
and i'm here a new question it says a
and b
are points on a circle with center row c
is a point on the circle such that oc
bisects angle aob
prove that oc bisects the arc a b
so without wasting much time let's have
a look at the solution
we will first look at the given part
so we have been given
a circle let's center
o
in which
a and b
are two points
on the circle
also we have been given that c is
another point
such that
angle aoc
is equals to angle boc
what we are required to prove here
let our ac is equals to our pc
let's look at the proof
so we know that oc is the bisector
of angle aob
right so which means that angle
aoc is equals to angle boc
right but these are the angles obtained
by the arc ac and bc
so for subtended i am writing suv only
which means that arc ac equals to r
bc
i hope my students got this question
well do not forget to hit the subscribe
button
you can also share your doubts in the
comment section see you next time bye"
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