A and B are points on a circle with center O. C is a point on the circle such that OC
bisects ∠AOB, prove that OC bisects the arc AB.
Given: in a given circle with center O, A
And B is Two points on the circle. C i
another point on the circle such that
∠AOC = ∠BOC
To prove : arc AC = arc BC
Proof: OC is the bisector of ∠AOB
Or ∠AOC = ∠BOC
But these are the angle subtended by the
arc AC and BC
arc AC = arc BC.
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