A can do a work in 6 days and B can do it in 8 days. They worked together for 2 days and then B left the work. How many days will A require to finish the work?
Given:
A can do a work in = 6 days
A’s, 1 day work = 1/6
B can do a work in = 8 days
B’s, 1 day work = 1/8
Both (A+B)’s 1 day work = 1/6 + 1/8
= (4+3)/24
= 7/24
Both (A+B)’s 2-day work = 2 × (7/24)
= 7/12
So, the remaining work = 1 – 7/12
= (12-7)/12
= 5/12
Now,
It is given that, A can do a work in = 6 days
A can-do 5/12 work in = 6 × (5/12) days
= 5/2 days
= 2 ½ days
∴ A can finish the work in 2 ½ days.
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