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**A can do a work in 6 days and B can do it in 8 days. They worked together for 2 days and then B left the work. How many days will A require to finish the work?**

Answer:

Given:

A can do a work in = 6 days

A’s, 1 day work = 1/6

B can do a work in = 8 days

B’s, 1 day work = 1/8

Both (A+B)’s 1 day work = 1/6 + 1/8

= (4+3)/24

= 7/24

Both (A+B)’s 2-day work = 2 × (7/24)

= 7/12

So, the remaining work = 1 – 7/12

= (12-7)/12

= 5/12

Now,

It is given that, A can do a work in = 6 days

A can-do 5/12 work in = 6 × (5/12) days

= 5/2 days

= 2 ½ days

∴ A can finish the work in 2 ½ days.

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