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Percentage | Percentage Exercise 7.3

Question 6

A shopkeeper marks his goods at such a price that would give him a profit of 10% after allowing a

discount of 12%. If an article is marked at ₹ 2250, find its:

(i) selling price

(ii) cost price.

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(i) It is given that

M.P. of an article = ₹ 2250

Discount = 12 %

We know that

S.P. = [1 – d/100] of M.P.

Substituting the values

S.P. = [1 – 12/100] of ₹ 2250

By taking LCM

S.P. = (100 – 12)/100 × 2250

By further calculation

S.P. = 88/100 × 2250

So we get

S.P. = 88/4 × 90

S.P. = 22 × 90

S.P. = ₹ 1980

(ii) It is given that

S.P. = ₹ 1980

Profit = 10%

We know that

S.P. = [1 + P/100] of C.P.

Substituting the values

1980 = [1 + 10/100] of C.P.

By further calculation

1980 = 110/100 of C.P.

So we get

C.P. = 1980 × 100/100

C.P. = 18 × 100

C.P. = ₹ 1800

Therefore, the cost price is ₹ 1800.

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Our top 5% students will be awarded a special scholarship to Lido.

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Question 6

A shopkeeper marks his goods at such a price that would give him a profit of 10% after allowing a

discount of 12%. If an article is marked at ₹ 2250, find its:

(i) selling price

(ii) cost price.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

(i) It is given that

M.P. of an article = ₹ 2250

Discount = 12 %

We know that

S.P. = [1 – d/100] of M.P.

Substituting the values

S.P. = [1 – 12/100] of ₹ 2250

By taking LCM

S.P. = (100 – 12)/100 × 2250

By further calculation

S.P. = 88/100 × 2250

So we get

S.P. = 88/4 × 90

S.P. = 22 × 90

S.P. = ₹ 1980

(ii) It is given that

S.P. = ₹ 1980

Profit = 10%

We know that

S.P. = [1 + P/100] of C.P.

Substituting the values

1980 = [1 + 10/100] of C.P.

By further calculation

1980 = 110/100 of C.P.

So we get

C.P. = 1980 × 100/100

C.P. = 18 × 100

C.P. = ₹ 1800

Therefore, the cost price is ₹ 1800.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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