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ML Aggarwal Solutions Class 8 Mathematics Solutions for Percentage Exercise 7.3 in Chapter 7 - Percentage
Prev
A dealer gave a 9% discount on an electric fan and charges ₹ 728 from the customer. Find the marked
price of the fan.
Answer:
Consider ₹ x as the M.P. of the fan
Discount = 9%
We know that
Amount of discount = 9% of ₹ x
It can be written as
= 9/100 × x
= ₹ 9x/100
Here
Charges for customer = ₹ x - ₹9x/100
Substituting the values
728 = (100x – 9x)/ 100
By further calculation
728 = 91x/100
So we get
x = (728 × 100)/ 91
x = 8 × 100
x = 800
Therefore, the marked price of the fan is ₹ 800.
Video transcript
"hello everybody welcome to lido learning
channel
my name is rachna chaudhary and let's
solve the question
which is a dealer gave nine percent
discount
on an electric fan and charges rupees
728 from the customer so
this is the price that customer has
paid so that mean this is the selling
price
of the fan we have to find the marked
price
so let us consider
the marked price is x
now discount is nine percent given
so nine percent we know that is always
calculated of
marked price discount is calculated of
marked price
so we have nine upon hundred
multiplied by x so
9 x upon 100 this is the discount in
rupees
now selling price we know
the formula of selling price is always
marked price
minus
discount in rupees
selling price is given to us in the
question let's substitute the values
728 marked price is
x this count is 9x upon 100 let's solve
the right hand side first of
all
so it would be 100x minus 9x
upon 100
so 728 is equal to
91 x upon 100 let's transpose 91 upon
100 to the left hand side
so it would be multiplying 728
by flipping
now we have to solve this
we can simplify it by um 91 itself
so after this simplification we would
have
8 so 8
multiplied by 100 is equal to x
that mean the value of x is 800 rupees
that means it is marked price
because we let x as marked price so
rupees 800
is the marked price i hope you
understand the method
see you in my next video thank you for
watching it
don't forget to like share and subscribe
leader learning channel
"
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