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Percentage | Percentage Exercise 7.3

Question 10

A shopkeeper allows a 20% discount on his goods and still earns a profit of 20%. If an article is sold for ₹ 360, find:

(i) the marked price

(ii) the cost price

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(i) It is given that

The dealer allows a discount of 20%

S.P. = [1 – d/100] of M.P.

Substituting the values

360 = [1 – 20/100] of M.P.

By further calculation

360 = 80/100 of M.P.

It can be written as

M.P. = 360 × 100/80

M.P. = 360 × 10/8

So we get

M.P. = 45 × 10

M.P. = ₹ 450

(ii) Consider ₹ x as the C.P. of the article

Profit = 20%

S.P. = ₹ 360

We know that

S.P. = [1 + P/100] of C.P.

Substituting the values

360 = [1 + 20/100] of x

By further calculation

360 = [1 + 1/5] of x

So we get

360 = 6x/5

By cross multiplication

x = 360 × 5/6

x = 60 × 5

x = ₹ 300

Therefore, the C.P. of the article is ₹ 300.

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Question 10

A shopkeeper allows a 20% discount on his goods and still earns a profit of 20%. If an article is sold for ₹ 360, find:

(i) the marked price

(ii) the cost price

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

(i) It is given that

The dealer allows a discount of 20%

S.P. = [1 – d/100] of M.P.

Substituting the values

360 = [1 – 20/100] of M.P.

By further calculation

360 = 80/100 of M.P.

It can be written as

M.P. = 360 × 100/80

M.P. = 360 × 10/8

So we get

M.P. = 45 × 10

M.P. = ₹ 450

(ii) Consider ₹ x as the C.P. of the article

Profit = 20%

S.P. = ₹ 360

We know that

S.P. = [1 + P/100] of C.P.

Substituting the values

360 = [1 + 20/100] of x

By further calculation

360 = [1 + 1/5] of x

So we get

360 = 6x/5

By cross multiplication

x = 360 × 5/6

x = 60 × 5

x = ₹ 300

Therefore, the C.P. of the article is ₹ 300.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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