A candidate who gets 36 marks in an examination fails by 24 marks but another candidate who gets 43 ...

Question

A candidate who gets 36 marks in an examination fails by 24 marks but another candidate who gets 43 marks gets 18 more marks than the minimum pass marks Find the maximum marks and the percentage of pass marks

Accepted Answer

Consider x as the maximum marks

Marks secured by the first candidate = 36% of x

It can be written as

= 36/100 × x

= 36x/ 100

Marks secured by another candidate = 43% of x

It can be written as

= 43/100 × x

= 43x/ 100

The qualifying marks are same for both the candidates

So according to the question

36x/100 + 24 = 43x/100 – 18

By further calculation

24 + 18 = 43x/100 – 36x/ 100

Taking LCM

42 = (43x – 36x)/ 100

42 = 7x/100

By cross multiplication

x = 42 × 100/7

x = 6 × 100

x = 600

Here the maximum marks = 600

Marks secured by first candidate = 36/100 × 600 = 36 × 6 = 216

Qualifying marks = 216 + 24 = 240

So the percentage of qualifying marks = (240/600 × 100) %

By further calculation

= 240/6 %

= 40 %

Hence, the maximum mark is 600 and the percentage of pass marks is 40%.

ML Aggarwal Solutions Class 8 Mathematics Solutions for Percentage Exercise 7.1 in Chapter 7 - Percentage