# ML Aggarwal Solutions Class 8 Mathematics Solutions for Percentage Exercise 7.1 in Chapter 7 - Percentage

Question 24 Percentage Exercise 7.1

A candidate who gets 36% marks in an examination fails by 24 marks but another candidate, who gets

43% marks, gets 18 more marks than the minimum pass marks. Find the maximum marks and the

percentage of pass marks.

Consider x as the maximum marks

Marks secured by the first candidate = 36% of x

It can be written as

= 36/100 × x

= 36x/ 100

Marks secured by another candidate = 43% of x

It can be written as

= 43/100 × x

= 43x/ 100

The qualifying marks are same for both the candidates

So according to the question

36x/100 + 24 = 43x/100 – 18

By further calculation

24 + 18 = 43x/100 – 36x/ 100

Taking LCM

42 = (43x – 36x)/ 100

42 = 7x/100

By cross multiplication

x = 42 × 100/7

x = 6 × 100

x = 600

Here the maximum marks = 600

Marks secured by first candidate = 36/100 × 600 = 36 × 6 = 216

Qualifying marks = 216 + 24 = 240

So the percentage of qualifying marks = (240/600 × 100) %

By further calculation

= 240/6 %

= 40 %

Hence, the maximum mark is 600 and the percentage of pass marks is 40%.

Related Questions

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!