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A box contains 17 cards numbered 1, 2, 3…….., 17 and are mixed thoroughly. A card is drawn at random from the box. Find the probability that the number on that card is

(i) odd

(ii) even

(iii) prime

(iv) divisible by 3

(v) divisible by 2 and 3 both

Answer:

Given A box contains 17 cards numbered 1 to 17 So, total number of outcomes = 17

(i) Card bearing odd number (1, 3, 5, 7, 9, 11, 13, 15, 17) = 9 Therefore, Probability P(E) = 9 / 17

(ii) Even number (2, 4, 6, 8, 10, 12, 14, 16) = 8 Therefore, Probability P(E) = 8 / 17

(iii) Prime numbers (2, 3, 5, 7, 11, 13, 17) = 7 Therefore,

Probability P(E) = 7 / 17

(iv) Numbers divisible by 3 3, 6, 9, 12, 15 = 5 Therefore, Probability P(E) = 5 / 17

(v) Numbers divisible by 2 and 3 both 6, 12 = 2 Therefore, Probability P(E) = 2 / 17

"hello everyone i am suman jaleen math
tutor from leader learning
welcome to question and answer session
given question is a box contains
17 cards numbered 1 2 3
and so on up to 17 and are mixed
thoroughly
a card is drawn at random from the box
find the probability that the number
on that card card is five different
conditions was given we need to
calculate we need to identify the
probability of these conditions
okay so first of all like yeah we need
to understand we need to understand the
card numbers that is from 1 to 17
1 2 3 4 5
6 7 8 9
10 11 12
13 14 15
16 17 okay
so out of this the odd numbers are 1
3 5 7
9 11 13
15 and 17 so there are eight
eight odd numbers okay so there are
not eight there are nine odd numbers
okay so the probability
is 9 out of 17
and the even numbers so the probability
of getting a card with even number
is 2 4 6
8 10 12 14 and 16
okay so these are
these are eight numbers so 8 out of 17
is the probability and the third
question is a prime number
prime number is nothing but which is
having two factors only
one and the same number okay one and the
same number
so here the prime numbers are 2
3 5 7
11 13
17. these are the prime numbers there
are totally seven prime numbers
so the probability is 7 out of 17
okay so and the fourth condition is
divisible by
3 okay the numbers here divisible by 3
are
3 6 9 12
15 15 that's it okay so there are five
outcomes so 5 out of 17 is the answer
and the last question is divisible by
both 2 and 3
so the numbers which are divisible by
both 2 and 3
are first of all 6 12
6 12 that's it only two numbers
so the probability is 2 out of 17
okay so this is the probability
and the answer hope you understand if
you have further questions
reach us at comment section and
subscribe to the channel leader learning
for further queries
thank you
"

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