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A die is rolled once. Find the probability of getting

(i) an even number

(ii) a multiple of 3

(iii) not a multiple of 3

Answer:

Total outcomes of a die when rolled once: 1, 2, 3, 4, 5, 6 = 6

(i) An even number: 2, 4, 6 i.e, Favourable outcomes = 3 Therefore, Probability P(E) = 3 / 6 = 1 / 2

(ii) Multiple of 3 = 3, 6 i.e, Favourable outcomes = 2 Therefore, Probability P(E) = 2 / 6 = 1 / 3

(iii) Not a multiple of 3 = 1, 2, 4, 5 i.e Favourable outcomes = 4

Therefore, Probability P(E) = 4 / 6 = 2 / 3

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