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ML Aggarwal Solutions Class 8 Mathematics Solutions for Mensuration Exercise 18.4 in Chapter 18 - Mensuration

Question 6 Mensuration Exercise 18.4

The floor of a rectangular hall has a perimeter of 236 m. Its height is 4·5 m. Find the cost of painting its four walls (doors and windows be ignored) at the rate of Rs. 8.40 per square meter.

Answer:

Given,

The perimeter of Hall = 236 m.

Height = 4.5 m

Perimeter = 2 (l + b) = 236 m

Area of four walls = 2 (l + b) × h

= 236 × 4.5

= 1062 m2

We have, cost of painting 1 m2 = ₹8.40

Hence,

Cost of painting 1062 m2 = ₹8.40 × 1062 = ₹8920.80

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