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ML Aggarwal Solutions Class 8 Mathematics Solutions for Mensuration Exercise 18.4 in Chapter 18 - Mensuration

Question 5 Mensuration Exercise 18.4

A swimming pool is 50 m in length, 30 m in breadth, and 2.5 m in depth. Find the cost of cementing its floor and walls at the rate of ₹27 per square meter.

Answer:

Given,

Length of swimming pool = 50 m

The breadth of swimming pool = 30 m

Depth (Height) of swimming pool = 2·5 m

Now,

Area of floor = 50 × 30 = 1500 m2

Area of four walls = 2 (50 + 30) × 2.5 = 160 × 2.5 = 400 m2

So, the area to be cemented = 1500 m2 + 400 m2 = 1900 m2

Cost of cementing 1m2 = ₹27

Hence,

Cost of cementing 1900m= ₹27 × 1900 = ₹51300

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