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ML Aggarwal Solutions Class 8 Mathematics Solutions for Mensuration Exercise 18.4 in Chapter 18 - Mensuration
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A swimming pool is 50 m in length, 30 m in breadth, and 2.5 m in depth. Find the cost of cementing its floor and walls at the rate of ₹27 per square meter.
Answer:
Given,
Length of swimming pool = 50 m
The breadth of swimming pool = 30 m
Depth (Height) of swimming pool = 2·5 m
Now,
Area of floor = 50 × 30 = 1500 m2
Area of four walls = 2 (50 + 30) × 2.5 = 160 × 2.5 = 400 m2
So, the area to be cemented = 1500 m2 + 400 m2 = 1900 m2
Cost of cementing 1m2 = ₹27
Hence,
Cost of cementing 1900m2 = ₹27 × 1900 = ₹51300
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