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**A closed rectangular wooden box has inner dimensions 90 cm by 80 cm by 70 cm. Compute its capacity and the area of the tin foil needed to line its inner surface.**

Answer:

Given,

Inner length of rectangular box = 90 cm

Inner breadth of rectangular box = 80 cm

Inner height of rectangular box = 70 cm

Now,

The capacity of rectangular box = Volume of a rectangular box

= l × b × h

= 90 cm × 80 cm × 70 cm

= 504000 cm^{3}

And,

Required area of tin foil = 2 (lb + bh + lh)

= 2(90 × 80 + 80 × 70 + 90 × 70) cm^{2}

= 2(7200 + 5600 + 6300) cm^{2}

= 2 × 19100 cm^{2}

= 38200 cm^{2}

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