Ml aggarwal solutions Our top 5% students will be awarded a special scholarship to Lido.
Set your child up for success with Lido, book a class today!

A road roller has a diameter of 0.7 m and its width is 1.2 m. Find the least number of revolutions that the roller must take in order to level a playground of size 120 m × 44 m. Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Given,

Diameter of a road roller = 0.7 m = 70 cm

So, radius (r) = 70/2 cm = 35 cm = 35/100 m

and width (h) = 1.2 m

Now,

Curved surface area = 2πrh

= (2 × 22/7 × 35/100 × 1.2) m2

= 264/100 m2

Area of playground = 120 m × 44 m

= 120 × 44 m2

= 5280 m2

Hence, the number of revolution made by the road roller = (5280/264) × 100

= 2000 revolutions

Our top 5% students will be awarded a special scholarship to Lido. Lido

Courses

Teachers

Book a Demo with us

Syllabus

Science
English
Coding

Terms & Policies

NCERT Question Bank

Maths
Science

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry