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Mensuration | Mensuration Exercise 18.3

Question 5

A rectangular pit 1.4 m long, 90 cm broad, and 70 cm deep was dug and 1000 bricks of base 21 cm by 10.5 cm were made from the earth dugout. Find the height of each brick.

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Here l = 1.4 m = 140 cm, b = 90 cm and h = 70 cm

The volume of rectangular pit = l × b × h

= (140 × 90 × 70) cm3

= 882000 cm3

Volume of brick = 21 × 10.5 × h

Now,

Number of bricks = Volume of pit/ Volume of brick

1000 = 882000/ (21 × 10.5 × h)

h = 882000/ (21 × 10.5 × 1000)

= 4 cm

Thus, the height of each brick is 4 cm.

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Question 5

A rectangular pit 1.4 m long, 90 cm broad, and 70 cm deep was dug and 1000 bricks of base 21 cm by 10.5 cm were made from the earth dugout. Find the height of each brick.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Here l = 1.4 m = 140 cm, b = 90 cm and h = 70 cm

The volume of rectangular pit = l × b × h

= (140 × 90 × 70) cm3

= 882000 cm3

Volume of brick = 21 × 10.5 × h

Now,

Number of bricks = Volume of pit/ Volume of brick

1000 = 882000/ (21 × 10.5 × h)

h = 882000/ (21 × 10.5 × 1000)

= 4 cm

Thus, the height of each brick is 4 cm.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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