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ML Aggarwal Solutions Class 8 Mathematics Solutions for Mensuration Exercise 18.1 in Chapter 18 - Mensuration

Question 4 Mensuration Exercise 18.1

Rajesh has a square plot with the measurement as shown in the given figure. He wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ₹50 per m2.

Question 4 Image - M L Aggarwal - Understanding ICSE Mathematics - Class 8  chapter Mensuration

Answer:

Given,

Side of square plot = 24 m

Length of house (l) = 18 m

and breadth (b) = 12m

Now,

Area of square plot = (24)2 m2 = (24 × 24) m2 = 576 m2

And,

Area of house = 18 × 12 = 216 m2

Remaining area of the garden = 576 m2 – 216 m2 = 360 m2

The cost of developing the garden = ₹50 per m2

Therefore, the total cost = ₹50 × 360 = ₹18000

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