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ML Aggarwal Solutions Class 8 Mathematics Solutions for Mensuration Exercise 18.1 in Chapter 18 - Mensuration
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A rectangle is 16 m by 9 m. Find a side of the square whose area equals the area of the rectangle. By how much does the perimeter of the rectangle exceed the perimeter of the square? Solution:
Answer:
Area of rectangle = (16 × 9) m2 = 144 m2
Given condition,
Area of square = Area of rectangle
∴ (Side)2 = 144
Side = √144 = 12 m
Now,
Perimeter of square = 4 × side = 4 × 12 = 48 m
Perimeter of rectangle = 2(l + b) = 2 (16 + 9) = 50 m
Hence, difference in their perimeters = 50 – 48 = 2 m
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