# ML Aggarwal Solutions Class 8 Mathematics Solutions for Mensuration Exercise 18.1 in Chapter 18 - Mensuration

Question 1 Mensuration Exercise 18.1

The length and breadth of a rectangular field are in the ratio 9: 5. If the area of the field is 14580 square meters, find the cost of surrounding the field with a fence at the rate of ₹3.25 per meter. Solution:

Let the length of the rectangle be 9x and its breadth be 5x

So,

Area = l × b

⇒ 14580 = 9x × 5x

45x2 = 14580

x2 = 14580/45 = 324

x = √324

x = 18

Hence,

Length = 9 × 18 = 162 m and Breadth = 5 × 18 = 90 m

Now, Perimeter = 2(l + b)

= 2 (162 + 90) = 2(252)

= 504 m.

Therefore, the cost for fencing the surrounding 504 m at the rate of ₹3.25 per meter = ₹(504 × 3.25) = ₹1638

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