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**A local bus is carrying 40 passengers, some with Rs 5 tickets, and the remaining with Rs 7.50 tickets. If the total receipts from these passengers are Rs 230, find the number of passengers with Rs 5 tickets.**

Answer:

Let the number of passengers with Rs 5 tickets = x

Then, the number of passengers with Rs 7.50 tickets = (40 – x)

According to the given statement,

5 × x + (40 – x) × 7.50 = 230

On simplification, we get,

5x + 300 – 7.5x = 230

5x – 7.5x = 230 – 300

-2.5x = - 70

x = -70 / - 2.5

We get,

x = 28

Therefore, the number of passengers with Rs 5 tickets = 28

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