A local bus is carrying 40 passengers, some with Rs 5 tickets, and the remaining with Rs 7.50 tickets. If the total receipts from these passengers are Rs 230, find the number of passengers with Rs 5 tickets.
Let the number of passengers with Rs 5 tickets = x
Then, the number of passengers with Rs 7.50 tickets = (40 – x)
According to the given statement,
5 × x + (40 – x) × 7.50 = 230
On simplification, we get,
5x + 300 – 7.5x = 230
5x – 7.5x = 230 – 300
-2.5x = - 70
x = -70 / - 2.5
We get,
x = 28
Therefore, the number of passengers with Rs 5 tickets = 28
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