Jump to

- Rational Numbers
- Exponents and Powers
- Squares and Square Roots
- Cubes and Cube Roots
- Playing with Numbers
- Operation on sets Venn Diagrams
- Percentage
- Simple and Compound Interest
- Direct and Inverse Variation
- Algebraic Expressions and Identities
- Factorisation
- Linear Equations and Inequalities In one Variable
- Understanding Quadrilaterals
- Constructions of Quadrilaterals
- Circle
- Symmetry Reflection and Rotation
- Visualising Solid Shapes
- Mensuration
- Data Handling

**A father is 7 times as old as his son. Two years ago, the father was 13 times as old as his son. How old are they now?**

Answer:

Let the present age of son be x years

Then, age of his father will be 7x years

Two years ago, age of son = (x – 2) years

Two years ago, age of his father = (7x – 2) years

According to the given problem,

7x – 2 = 13 (x – 2)

7x – 2 = 13x – 26

7x – 13x = - 26 + 2

-6x = - 24

x = - 24 /- 6

We get,

x = 4

Therefore, age of son = 4 years and

Age of his father = 7x = 7 × 4 = 28 years

Related Questions

Was This helpful?

Exercises

Chapters

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2022 © Quality Tutorials Pvt Ltd All rights reserved