 # ML Aggarwal Solutions Class 8 Mathematics Solutions for Linear Equations and Inequalities In one Variable Exercise 12.2 in Chapter 12 - Linear Equations and Inequalities In one Variable

Question 13 Linear Equations and Inequalities In one Variable Exercise 12.2

A father is 7 times as old as his son. Two years ago, the father was 13 times as old as his son. How old are they now?

Let the present age of son be x years

Then, age of his father will be 7x years

Two years ago, age of son = (x – 2) years

Two years ago, age of his father = (7x – 2) years

According to the given problem,

7x – 2 = 13 (x – 2)

7x – 2 = 13x – 26

7x – 13x = - 26 + 2

-6x = - 24

x = - 24 /- 6

We get,

x = 4

Therefore, age of son = 4 years and

Age of his father = 7x = 7 × 4 = 28 years

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