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Selina Solutions Class 9 Chemistry Solutions for Exercise Number Problems in Chapter 7 - Chapter 7 Study Of Gas Laws

Question 4 Number Problems

800 cm3 of gas is collected at 654 mm pressure. At what pressure would the volume of the gas reduce by 40% of its original volume, the temperature remaining constant.

Answer:

= 800 cm3

P = 650 m

P1=?

V1 = reduced volume = 40% of 800

= 80 x 40/100

= 320

Net V1 = 800 - 320 = 480 cm3

T = T1

Using the gas equation,

PV/T = P1V1/T1

= 800x 650

T

= P1 x 480/T1

Since T = T1

= 800x 650/480

= 1083.33 mm of Hg.

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